NTA CSIR UGC NET Answer Key 2025
📖 About NTA CSIR UGC NET Answer Key 2025
NTA CSIR UGC NET Answer Key 2025 is a answer key release featured on SarkariResultsInd. On this page we have brought together the key details — important dates, eligibility and age limit, application fee, and the official links — so you can review the complete notification in one place before acting on it.
Calculate a tentative score from the official key, then wait for the final key if objections are invited. Do not rely on unofficial keys for cut-off guesses.
To view the answer key, open the official link in the Important Links section above. If you disagree with any answer, note the objection window and raise objections through the official portal — a small fee per question usually applies.
Always cross-check every detail with the official notification before you apply. SarkariResultsInd is an independent information portal and is not affiliated with any government department or recruiting agency. Last synced on this site: 09 July 2026.
Key Details at a Glance
- Application Begin
- 09/12/2024
- Last Date for Apply Online
- 02/01/2025
- Pay Exam Fee Last Date
- 03/01/2025
- General
- 1150/-
- OBC / EWS
- 600/-
- Maximum Age
- 30 Years for JRF Only.
What to Do Next
- 1 Open the answer key or response sheet link from the Important Links section.
- 2 Compare your responses with the official key and note any doubtful questions.
- 3 Submit objections only through the official portal within the given window.
Frequently Asked Questions
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📝 Short Information
Council of Scientific & Industrial Research and National Testing Agency (NTA) has relased CSIR UGC NET / JRF Exam December 2024 Notification. Those candidates who are interested in this CSIR UGC NET December 2024 Exam can Check Result with Score Card. Read the notification for NTA CSIR UGC NET Exam, eligibility, Subject Details information, Document Required, age limit,
Pay the Examination Fee Through Debit Card / Credit Card / Net Banking / UPI Only.
NTA CSIR UGC NET Examination December 2024
Chemical Science — M.Sc / Equivalent Degree with 55% Marks for General / OBC Candidates. For SC / ST and PH Candidates : 50% Marks. Integrated Course and B.E/ B.Tech / B.Pharma and MBBS Candidates Are Also Eligible for CSIR NET 2024.
🔗 Important Links
🌐 Official Website
https://csirnet.nta.ac.in/📤 Share This Post
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